2n^2+4n+6=4

Solution for 2n^2+4n+6=4 equation:

Simplifying
2n2 + 4n + 6 = 4

Reorder the terms:
6 + 4n + 2n2 = 4

Solving
6 + 4n + 2n2 = 4

Solving for variable 'n'.

Reorder the terms:
6 + -4 + 4n + 2n2 = 4 + -4

Combine like terms: 6 + -4 = 2
2 + 4n + 2n2 = 4 + -4

Combine like terms: 4 + -4 = 0
2 + 4n + 2n2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(1 + 2n + n2) = 0

Factor a trinomial.
2((1 + n)(1 + n)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(1 + n)' equal to zero and attempt to solve:

Simplifying
1 + n = 0

Solving
1 + n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + n = 0 + -1

Combine like terms: 1 + -1 = 0
0 + n = 0 + -1
n = 0 + -1

Combine like terms: 0 + -1 = -1
n = -1

Simplifying
n = -1
Subproblem 2
Set the factor '(1 + n)' equal to zero and attempt to solve:

Simplifying
1 + n = 0

Solving
1 + n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + n = 0 + -1

Combine like terms: 1 + -1 = 0
0 + n = 0 + -1
n = 0 + -1

Combine like terms: 0 + -1 = -1
n = -1

Simplifying
n = -1
Solution
n = {-1, -1}